Investigation 14

Results:

| Beaker (initial) | Beaker (after reaction) | CO2 lost |

Trial 1 | 30.394g | 42.725g | Inconclusive |

Trial 2 | 30.394g | 42.583g | inconclusive |

Trial 3 | 28.720g | 42.482g | Inconclusive |

Table 1: Reactions of HCl acid

| Beaker (initial) | Beaker (after reaction) | CO2 lost |

Trial (supervised) | 30.412g | 41.663g | .098g |

Calculations:

Equation 1: HCl (aq) + NaHCO3(s) NaCl (aq) + H20

H2CO3 (aq) H2O(aq) + CO2 (g)

Trial 1: 42.725g-(30.394g+.5g)=12.831g (CO2 released)

12.831gx(1 mol CO2/44.01g CO2)x(1 mol NaHCO3/1 mol CO2)x(84.01g NaHCO3/1 mol NaHCO3)=24.492g NaHCO3

Mass Percent= (12.831g /0.5g)=25.662gx100=2566.2% ERROR

Trial 2: 42.583g-(30.394g-.5)=12.689g (CO2 released)

12.689gx(1 mol CO2/44.01g CO2)x(1 mol NaHCO3/1 mol CO2)x(84.01g NaHCO3/1 mol NaHCO3)= 24.221g NaHCO3

Mass Percent= (12.689g/0.5g)=25.378gx100=2537.8% ERROR

Trial 3: 42.482g-(28.720g-.5)=14.262g (CO2 lost)

14.262gx(1 mol CO2/44.01g CO2)x(1 mol NaHCO3/1 mol CO2)x(84.01g NaHCO3/1 mol NaHCO3)=27.225g NaHCO3

Mass Percent= (14.262g/.5g)=28.524gx10= 2852.4% ERROR

Trial (supervised)-

41.663g-(30.412g-.257g)=10.751 (CO2 lost)

11.508gx(1 mol CO2/44.01g CO2)x(1 mol NaHCO3/1 mol CO2)x(84.01g NaHCO3/1 mol NaHCO3)= 21.967g NaHCO3

Mass Percent= (10.751g/0.5g)=2150%

Discussion:

Based on the results in table one there must have been some error based on the inconclusive results. In trial one there was some confusion about how to get started and making long decisions about how to go about doing calculations. Based on the results above in table 1 and 2 there wasn’t enough data to check on what went wrong. The amount of acid used was based off of the calculation by converting 0.500g NaHCO3 6.00 mL HCl (the amount was then doubled to 12mL to make sure enough acid was able to dissolve the mixture.

Finding the limiting reactant from this particular experiment was hard to determine because we had inconclusive numbers due to error in some area during lab. The...