Solutions for Computer Architechture

Chapter 1 Solutions Chapter 2 Solutions Chapter 3 Solutions Chapter 4 Solutions Chapter 5 Solutions Chapter 6 Solutions Appendix A Solutions Appendix B Solutions Appendix C Solutions

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Copyright © 2012 Elsevier, Inc. All rights reserved.

Solutions to Case Studies and Exercises

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Copyright © 2012 Elsevier, Inc. All rights reserved.

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Solutions to Case Studies and Exercises

Chapter 1 Solutions

Case Study 1: Chip Fabrication Cost

1.1 0.30 × 3.89 –4 a. Yield = ⎛ 1 + -------------------------- ⎞ = 0.36 ⎝ ⎠ 4.0 b. It is fabricated in a larger technology, which is an older plant. As plants age, their process gets tuned, and the defect rate decreases. 1.2 π × 30 π × ( 30 ⁄ 2 ) a. Dies per wafer = ---------------------------- – ------------------------------ = 471 – 54.4 = 416 1.5 sqrt ( 2 × 1.5 ) 0.30 × 1.5 –4 Yield = ⎛ 1 + ----------------------- ⎞ = 0.65 ⎝ 4.0 ⎠ Profit = 416 × 0.65 × $20 = $5408 π × 30 π × ( 30 ⁄ 2 ) b. Dies per wafer = ---------------------------- – ------------------------------ = 283 – 42.1 = 240 2.5 sqrt ( 2 × 2.5 ) 0.30 × 2.5 – 4 Yield = ⎛ 1 + -------------------------⎞ = 0.50 ⎝ ⎠ 4.0 Profit = 240 × 0.50 × $25 = $3000 c. The Woods chip d. Woods chips: 50,000/416 = 120.2 wafers needed Markon chips: 25,000/240 = 104.2 wafers needed Therefore, the most lucrative split is 120 Woods wafers, 30 Markon wafers. 1.3 0.75 × 1.99 ⁄ 2 –4 a. Defect – Free single core = ⎛ 1 + --------------------------------- ⎞ = 0.28 ⎝ ⎠ 4.0 No defects = 0.282 = 0.08 One defect = 0.28 × 0.72 × 2 = 0.40 No more than one defect = 0.08 + 0.40 = 0.48 Wafer size b. $20 = ----------------------------------old dpw × 0.28 $20 × 0.28 = Wafer size/old dpw Wafer size $20 × 0.28 x = ------------------------------------------------- = ------------------------1/2 × old dpw × 0.48 1/2 × 0.48 = $23.33

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Copyright © 2012 Elsevier, Inc. All rights reserved.

Chapter 1 Solutions

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Case Study 2: Power Consumption in...