# Ten and One

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Date Submitted: 03/12/2011 09:23 PM

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A.

1.

Decision Variables

X1 = # of Slices of Pizza

X2 = # of Hot Dogs

X3 = # of BBQ Sandwiches

2. Objective Function

X1 X2 X3

Selling Price 1.50 1.50 2.25

-Cost .75 .45 .90

Profit .75 1.05 1.35

The objective function in Julie’s Food Booth is to maximize total profit.

Z= 0.75X1 + \$1.05X2 = \$1.35X3

3. Contraints

a. Budget = .75X1 = .45X2 + .90X3 = X2 + X3

d. At least sell twice as many hotdogs as BBQ sandwiches ( X2 – 2X3 >= 0)

Model:

Maximize Total profit Z = \$0.75X1 + 1.10X2 +1.25X3

Subject to:

0.75X1+0.50X2+1.00X3=0 (at least twice as many hot dogs as BBQ sandwiches

B. Evaluate the propect of borrowing Money before the first game.

Julie will need to borrow money due to the cost of the booth and oven. With the amount of money she currently has is not enough to purchase her food items.

C. Evaluate the prospect of paying a friend \$100/game to assist.

Due to Julie expenses I don’t think she will be able to pay a friend \$100 for each game to help.

D. Julie must consider the weather and even if the game is crowed I don’t see this being very profitable for Julie due the high cost of the booth. She will not profit enough to cover booth fees and food.

A.

1.

Decision Variables

X1 = # of Slices of Pizza

X2 = # of Hot Dogs

X3 = # of BBQ Sandwiches

2. Objective Function

X1 X2 X3

Selling Price 1.50 1.50 2.25

-Cost .75 .45 .90

Profit .75 1.05 1.35

The objective function in Julie’s Food Booth is to maximize total profit.

Z= 0.75X1 + \$1.05X2 = \$1.35X3

3. Contraints

a. Budget = .75X1 = .45X2 + .90X3 = X2 + X3

d. At least sell twice as many hotdogs as BBQ sandwiches ( X2 – 2X3 >= 0)

Model:

Maximize Total profit Z = \$0.75X1 + 1.10X2 +1.25X3

Subject to:

0.75X1+0.50X2+1.00X3=0 (at least twice as many hot dogs as BBQ sandwiches

B. Evaluate the propect of borrowing Money before the first game.

Julie will need to borrow money due to the cost of the booth and oven. With the amount of money she currently has is not...