Charle's Law

Data

ATM: 764 mmHG

Boyles Law Pressure and Volume

Charles Law Length/Temp

Length(cm) | Temp(deg.C) | Length/Temp |

2.11 cm | 5 Celsius | 0.422 L/T |

2.2 cm | 10 Celsius | 0.22 L/T |

2.3 cm | 20 Celsius | 0.115 L/T |

2.35 cm | 30 Celsius | 0.078333333 L/T |

2.41 cm | 40 Celsius | 0.06025 L/T |

2.5 cm | 50 Celsius | 0.05 L/T |

2.55 cm | 60 Celsius | 0.0425 L/T |

2.6 cm | 70 Celsius | 0.037142857 L/T |

2.67 cm | 80 Celsius | 0.033375 L/T |

2.72 cm | 90 Celsius | 0.030222222 L/T |

2.76 cm | 100 Celsius | 0.0276 L/T |

Calculations

Calculate Null Volume:

Multiply mass of null water times volume of the water at given temperature:

Water @ 22 Degrees C= .9978g/mL

(2.123g)/(.9978g/mL)= 2.128 mL

Calculate change in mmH20:

Height (funnel) – Height (buret) = Change in Height

ex:

579 mm- 579mm = 0mm Change in Height

Calculate change in height in mmHg; convert change in height (1mmHg=13.6mmH20)

Change in height/13.6

ex:

54 (mmH20)/13.6 (mmH20/mmHg)=3.97mmHg

Calculate Pressure: Add atmospheric pressure obtained to change in height mmHG

ex:

764mmHg+3.97mmHg=767.97mmHg

Calculate Corrected Air Volume: Add Null Volume to Buret Volume

ex:

21.2mL+2.13mL= 23.33mL

Calculate P*V using corrected values:

Pressure times Volume

ex:

764*23.33=17,824 mmHg*mL

Results and Discussion

Weight of 150mL Beaker (empty): 70.1751g

Temperature of Water: 25 ° C

Mass of Null Water: 2.128g

Density of Water @ 25 ° C: 0.99707g/mL

Volume of Null Water: 2.128g/0.99707g/mL = 2.13425mL

Both graphs looked as expected with out calculations. Although, as I said before if we were to change the second calculation within Boyles Law data we would have 99 percent accuracy. For the ∆h values of water, we took the height of the water in the funnel minus the height of the water in the Buret. As for our absolute value, some things that might have changed the results and deviated our calculations were our initial data.

Error analysis...