Submitted by: Submitted by tintinkaye
Views: 117
Words: 2439
Pages: 10
Category: Business and Industry
Date Submitted: 03/08/2014 06:37 AM
Northern Philippines College for Maritime, Science and Technology, Inc.
Mass = quantity of matter
EFFECT OF FORCE
=>the force acting on a body may
a) Change its state of rest or in motion
b) Accelerate or retard its motion
c) Keep it in equilibrium
d) Produces internal stress in the body
RESULTANT OF FORCES
SP-01] A force of 200lb is directed as shown. Det. The X & Y component.
Fx= F Cos Fy= Sin
= -200 Cos 30 = 200(Sin 30)
= -173.21lb = 100lb
SP-02] Determine the component of 300lb force directed down to the right at a slope of 2 to 3
2²+3²
13
=3.61
Fx= F Cos Fy= F Sin
= 300 Cos (3/3.61) = -300 Sin (2/3.61)
= 249.31lb = -166.20lb
SP-03] The component of a certain force are defined by Fx=300lb & Fy= -200lb Det. The magnitude & inclination with the axis.
F= (Fx)² + (Fy)² tan=Fy/Fx
= (300)² + (-200)² = -200lb / 300lb
= 361lb = -33.7
SW-01] The body on the 30 incline is acted upon by a force P at 20 inclination with the horizontal. If P is resolved into components parallel & perpendicular to the inclined & the value of the parallel component is 400lb, compute the value of the perpendicular component and P.
X axis = PH / P˶ / Px
Y axis = Pv / P / Py
tan= P/P˶ = 20+30 Equation x axis
P˶ = 400 = 50 Fx= F Cos
Fy= F Sin
P= P˶ tan P= 400² + 476.701²
= 400 tan 50 = 622.290lb
= 476.701lb...