Cv Homework1

Submitted by: Submitted by

Views: 37

Words: 410

Pages: 2

Category: Science and Technology

Date Submitted: 12/08/2014 09:25 PM

Report This Essay

Problem 1.

1.8 a. Because of that the transistor density increases by about 35% per year.

And (1.35)10=20.107 So the number of transistors on a chip in 2015 should be 20 times

the number in 2005.

b. Because of that the clock rates up almost 40% per year between 1986 and 2003.And the

Intel Pentium4 Xeon clock rates are 3200MHz in 2003.So the clock rates in 2015 would be

3200*(1.4)12 =181420 ≈181.4GHz

c. Because of that the the clock rates growing at less than 1% per year after 2003.

3200*(1.01)12 =3605 MHz

d. Power density has limited the rate of growth of the clock rate.

Now,density improvements have supported that introduction of multiple processors per

chip.

e. I guess that the approximate rate of growth for DRAM capacity by 2020 will be 20%.

Problem 2.

A.23

First of all,for desktop,I think we care about the speed of integer and floating-point units most,because nowadays people always care about the reaction speed of the applications.So the desktop ISA should be made capable of running the applications faster,and we do not care much about the power consumption for desktop.

However,for embedded computing,power consumption is a big concern.Although,the speed of integer is also important.But you can image,if your phone can only use for an hour,how bad would it be?So for embedded computing,ISA must consider saving energy.

For severs,I think we should care about the speed of integer,so that they can run the applications faster.And we also should care about that the ISA must support for high throughput and multiple users,for high throughput and multiple users are the features of severs.

For cloud computing,memory management is its feature,so the ISA must consider the cloud memory management.And we all know that the Security and encryption of user data will be important, so ISAs may provide support for these concerns.

Problem 3.

a. 185=[10111001] 122=[01111010]

10111001...