Submitted by: Submitted by CMCCLUNG1
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Words: 430
Pages: 2
Category: Other Topics
Date Submitted: 03/29/2015 02:18 AM
215.251.145.0/24 subnetted to 46 subnets and provide information for subnets #1, #4, #5, and #46
RED: Network Bits
Green: Host Bits
Yellow: Subnet Bits
Convert given IP to binary:
Network address: 11010111. 11111011. 10010001. 00000000
Change all Network Bits to 1’s to find Subnet Mask.
Subnet Mask: 11111111. 11111111. 11111111. 00000000
2x to find number of Host Bits to borrow for Subnet Bits. Keep looking for x until 2x = number of subnets, if number of subnets falls between two different x then take the greater x.
22 = 4
23 = 8
24 = 16
25 = 32
26 = 64
Need to borrow 6 host bits.
Network address: 11010111. 11111011. 10010001. 00000000
Subnet Mask: 11111111. 11111111. 11111111. 11111100
255. 255. 255. 252
1st Subnet: Subnet #1
Subnet number is 1, 1 binary 1. Using 6 host bits gives 000001.
Network address for Subnet 1: 11010111. 11111011. 10010001. 00000100
215. 251. 145. 4
To Get Broadcast Address, all Host bits become 1.
Broadcast Address: 11010111. 11111011. 10010001. 00000111
215. 251. 145. 7
Available Addresses are one above the Network address to one less than the Broadcast address.
Available Addresses: 215.251.145.5 – 215.251.145.6
2nd Subnet: Subnet #4
Subnet number is 4, 4 in binary is 100. Using 6 host bits gives 000100.
Network address for Subnet 1: 11010111. 11111011. 10010001. 00010000
215. 251. 145. 16
To Get Broadcast...