Spreadsheet Modeling

Spreadsheet Modeling & Decision Analysis, 5ed

Cliff T. Ragsdale

Check figures for selected odd problems.

Chapter 2

7. 9. 11. 13. 15. 17. 19. 21. 23. Optimal objective value = 10.55 Optimal objective value = 125 Optimal objective value = 154 Optimal objective value = 775 Optimal objective value = 32500 Optimal objective value = 0.75 Optimal objective value = 59300 Optimal objective value = 26000 Optimal objective value = 3.5 million

Chapter 3

3. 5. 7. 9. 11. 13. 15. 17. 19. 21. 23. 25. 27. 29. 31. 33. 35. 37. 39. 41. 43. 45. 47. Maximum profit = $775,000 Minimum cost per pound = $0.75 Maximum profit = $59,300 Maximum profit = $26,000 Minimal cost = $3.5 million c. Maximum revenue = $444,000 c. Maximum new customers = 113,500 b. Maximum return = 10.25% c. Maximum return = $8,898 (or 8.898%) c. Minimum cost = $1,049 (in $1,000s) c. Profit = $1,526,500 c. Minimum number of employees = 640 c. Maximum steam production = 32,174 pounds per ton c. Minimum transportation cost = $730 c. Minimum cost = $44,067.67 c. Maximum profit = $1,007,750 c. Profit = $669,000 c. Maximum profit = $29,100 c. Minimum investment = $38,149 b. Total Finance Charge = $22,878. Among other things, defer $3,000 in payments in March b. Total Profit = $1,309,900 b. Branches 1, 2, 6 & 8 are efficient

Chapter 4

3. 5. c. d. a. b. 6. c. b. 4.67 15.33. 0 The new objective would be unbounded. d. No. h. Every additional ton of concentrate unit shipped from Eustis to Miami would increase costs by $50. $225 The profit per acre of cantaloupes would have to increase by $99.50.

7. 9.

11. a. No. e. Yes. 13. c. Yes. Profits would increase by $7×1,000=$7,000. 15. b. This constraint is nonbinding and its RHS could by 0.15 without affecting the solution. 17. c. Regular octane rating = 90.0, supreme octane rating = 102.11. 19. b. Location 6. 21. b. Macon. Each additional unit of capacity there increases costs by $36.45 (which is the cheapest way to increase capacity). e. $1 extra. 23. c. $0. 25....