The Volume of a Mole of Gas

The Volume of a Mole of Gas

(Group 8)

Members:

Saon, Sheihaira S.

Oberio, Jan Philip L.

Laus, Lolyn Mae T.

Introduction

Solids, liquids and gases are called the three state of matter. The condition or state of a gaseous substance is determined by four properties: volume (V), pressure (P), temperature (T) and number of moles of the substance present (n). Equal volumes of gases at the same temperature and pressure contain equal number of particles. No matter what the size of the gas particle, large empty space exists between individual particles of gas. Because temperature and pressure affect the volume of a gas (↑T = ↑ V ↑P =↓V) we use a standard temperature and pressure (STP) to measure volume. Standard temperature is 0°C. Standard pressure is 1 atmosphere (atm).

At STP, 1mol of any gas occupies a volume of 22.4 L which is called standard molar volume. A mole of any substance contains Avogadro’s number of particles. Thus 22.4 L of any gas at STP contains 6.02 x 1023 representative particles of that gas. Take note that a mole of a gas (22.4 L at STP) has a mass equal to the gram formula mass. Only gases with equal gram formula masses would have equal masses for equal volumes at STP.

Formula

Volume of gas=moles of gas x 22.4 L1 mol

Derivation of the Standard Molar Volume

PV=nRT

where: P = 1.00 atm T = 273 K

n = 1.00 mol R = 0.0821

So, to solve for the volume the formula will be:

V= nRTP

so: V = (1.00 mol)(0.0821L x atmK x mol)(273 K)1.00 atm

= 22.4133 L1.00

= 22.4133 L

Following the correct significant figure which is three (3) the final answer is 22.4 L

Derivation on how to solve for the Moles of Gas

Volume of gas=moles of gas x 22.4 L1 mol

To find the moles of gas we shall divide 22.4 L1 mol for the both side of the equation.

Volume of gas22. 4 L1 mol=moles of gas x 22.4 L1 mol22.4 L1 mol

Then, cancel the same values in the left side and “moles of gas” will remain in the equation.

Volume of gas22. 4 L1...