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Chapter 1 Solutions
Chapter 2 Solutions
Chapter 3 Solutions
Chapter 4 Solutions
Chapter 5 Solutions
Chapter 6 Solutions
Appendix A Solutions
Appendix B Solutions
Appendix C Solutions
Copyright © 2012 Elsevier, Inc. All rights reserved.
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Solutions to Case Studies
and Exercises
Copyright © 2012 Elsevier, Inc. All rights reserved.
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2
■
Solutions to Case Studies and Exercises
Chapter 1 Solutions
Case Study 1: Chip Fabrication Cost
1.1
1
0.30 × 3.89 –4
a. Yield = ⎛ 1 + -------------------------- ⎞ = 0.36
⎝
⎠
4.0
b. It is fabricated in a larger technology, which is an older plant. As plants age,
their process gets tuned, and the defect rate decreases.
2
1.2
π × 30
π × ( 30 ⁄ 2 )
a. Dies per wafer = ---------------------------- – ------------------------------ = 471 – 54.4 = 416
1.5
sqrt ( 2 × 1.5 )
0.30 × 1.5 –4
Yield = ⎛ 1 + ----------------------- ⎞ = 0.65
⎝
4.0 ⎠
Profit = 416 × 0.65 × $20 = $5408
2
π × 30
π × ( 30 ⁄ 2 )
b. Dies per wafer = ---------------------------- – ------------------------------ = 283 – 42.1 = 240
2.5
sqrt ( 2 × 2.5 )
0.30 × 2.5 – 4
Yield = ⎛ 1 + -------------------------⎞ = 0.50
⎝
⎠
4.0
Profit = 240 × 0.50 × $25 = $3000
c. The Woods chip
d. Woods chips: 50,000/416 = 120.2 wafers needed
Markon chips: 25,000/240 = 104.2 wafers needed
Therefore, the most lucrative split is 120 Woods wafers, 30 Markon wafers.
1.3
0.75 × 1.99 ⁄ 2 –4
a. Defect – Free single core = ⎛ 1 + --------------------------------- ⎞ = 0.28
⎝
⎠
4.0
No defects = 0.282 = 0.08
One defect = 0.28 × 0.72 × 2 = 0.40
No more than one defect = 0.08 + 0.40 = 0.48
Wafer size
b. $20 = ----------------------------------old dpw × 0.28
$20 × 0.28 = Wafer size/old dpw
Wafer size
$20 × 0.28
x = ------------------------------------------------- = ------------------------1/2 × old dpw × 0.48
1/2 × 0.48
= $23.33
Copyright © 2012 Elsevier, Inc. All rights...
