Submitted by: Submitted by rominem
Views: 406
Words: 726
Pages: 3
Category: Science and Technology
Date Submitted: 05/19/2011 11:33 PM
Data
ATM: 764 mmHG
Boyles Law Pressure and Volume
Charles Law Length/Temp
Length(cm) | Temp(deg.C) | Length/Temp |
2.11 cm | 5 Celsius | 0.422 L/T |
2.2 cm | 10 Celsius | 0.22 L/T |
2.3 cm | 20 Celsius | 0.115 L/T |
2.35 cm | 30 Celsius | 0.078333333 L/T |
2.41 cm | 40 Celsius | 0.06025 L/T |
2.5 cm | 50 Celsius | 0.05 L/T |
2.55 cm | 60 Celsius | 0.0425 L/T |
2.6 cm | 70 Celsius | 0.037142857 L/T |
2.67 cm | 80 Celsius | 0.033375 L/T |
2.72 cm | 90 Celsius | 0.030222222 L/T |
2.76 cm | 100 Celsius | 0.0276 L/T |
Calculations
Calculate Null Volume:
Multiply mass of null water times volume of the water at given temperature:
Water @ 22 Degrees C= .9978g/mL
(2.123g)/(.9978g/mL)= 2.128 mL
Calculate change in mmH20:
Height (funnel) – Height (buret) = Change in Height
ex:
579 mm- 579mm = 0mm Change in Height
Calculate change in height in mmHg; convert change in height (1mmHg=13.6mmH20)
Change in height/13.6
ex:
54 (mmH20)/13.6 (mmH20/mmHg)=3.97mmHg
Calculate Pressure: Add atmospheric pressure obtained to change in height mmHG
ex:
764mmHg+3.97mmHg=767.97mmHg
Calculate Corrected Air Volume: Add Null Volume to Buret Volume
ex:
21.2mL+2.13mL= 23.33mL
Calculate P*V using corrected values:
Pressure times Volume
ex:
764*23.33=17,824 mmHg*mL
Results and Discussion
Weight of 150mL Beaker (empty): 70.1751g
Temperature of Water: 25 ° C
Mass of Null Water: 2.128g
Density of Water @ 25 ° C: 0.99707g/mL
Volume of Null Water: 2.128g/0.99707g/mL = 2.13425mL
Both graphs looked as expected with out calculations. Although, as I said before if we were to change the second calculation within Boyles Law data we would have 99 percent accuracy. For the ∆h values of water, we took the height of the water in the funnel minus the height of the water in the Buret. As for our absolute value, some things that might have changed the results and deviated our calculations were our initial data.
Error analysis...