Submitted by: Submitted by tglickman2
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Category: Business and Industry
Date Submitted: 01/10/2012 10:02 AM
Central Limit Theorem (Week 2)
QNT/561
January 5, 2011
Week 2 Assignment: Exercises 21, 22, and 34 (Ch. 8) of Statistical Techniques in Business & Economics:
#21 (a-c) a. The difference between the sample mean (bar X) and the population mean.
b. Yes.
c. The sample size is equal to the populations size
#22 (a-d) Reasons for sampling:
a. Time: Surveying and entire population can be time consuming. Sampling a small group can be quick and more efficient.
b. Cost: The cost to conduct a sampling will be more effective.
c. Accuracy: Small groups that are sampled can provide you with similar results in accuracy.
d. Destructive sampling -- for example, if you crash tested the entire population of cars for safety testing, you wouldn't have any left to drive -- so you only test a sample
#34 (a-e)
a. 5656.85
b. Normal distribution
c. z = (112000-110000)/5656.85
z = 0.353553
from a z table...
prob(z > 0.353553)
= 0.3618
excel:
=1-NORMDIST(112000,110000,5657,TRUE)
d. z = (100000-110000)/5656.85
z = -1.767768
from a table:
prob(z > -1.767768)
= 0.9615
in excel:
=1-NORMDIST(100000,110000,5657,TRUE)
e. Part D - Part C:
= 0.9615 - 0.3618
= 0.5997
excel:
=1-NORMDIST(100000,110000,5657,TRUE)-(1-NORMDIST(112000,110000,5657,TRUE))
Exercises 32, 34, and 46 (Ch. 9) of Statistical Techniques in Business & Economics
#32 mean - z*sd/sqrt(N) to mean + z*sd/sqrt(N)
z (from a table) is 1.96
N = 36
sd = 0.03
mean = 3.01 (continued next page)
3.01 - 1.96*0.03/sqrt(36) to 3.01 + 1.96*0.03/sqrt(36)
3.0002 to 3.0198
#34 n = 50, m = 26, s = 6.2,
SE of the mean = s/sqrt n = 6.2/sqrt 50 = 0.8768, z = 1.96
Margin of error: E = Z * SE = 1.96 * 0.8768 = 1.7186
Lower Limit of the confidence interval = m - E = 24.2814
Upper Limit of the confidence interval = m + E = 26 + 1.7186 = 27.7186
Therefore, the confidence interval...