Statistics Sas Project on Nicotine

1. Answer the following for the variables Carbon Monoxide and Tar

a. Intercept: 2.74328 Slope: .80098

b. Yes it is useful because of the strong correlation and R^2= .9168.

c. 91.68% of variation in carbon monoxide is explained by tar, which is high.

d. Yes there is an outlier. The observation number is 23.5.

i. Intercept: 1.41285 Slope:.92813

ii. Yes it is even more useful because now the correlation is stronger and R^2= .9335

iii. 93.35% of variation in carbon monoxide is explained by tar, which is high.

e. It fits a random pattern which means it is not evident.

f. Y=10.7533

2. Carbon Monoxide and Nicotine

a. Intercept: 1.66467 Slope: 12.39541

b. Yes because the P-Value is less than .0001 which is significantly smaller than alpha of .05 and because there is a strong correlation.

c. 85.74% of variation in carbon monoxide is explained by Nicotine, which is relatively high.

d. Yes there is an outlier and the observation number is 26.8273

i. Intercept: -.23818 Slope: 14.85998

ii. It is useful because the correlation is strong because R^2= .8658

iii. 86.58% of variation in carbon monoxide is explained by nicotine, which is high.

e. There is a cluster but no evident pattern. A transformation in Y may be necessary to confirm this.

f. Intercept: 1.29225 Slope: 1.28876, P-Value is less than .0001 which is significantly smaller than .05. R^2 is high at 68.26% of variation. It is relatively high. There are two outliers. There is a clump between -.25 and .25 & 1.75 and 3.0.

g. Y= 2.58101

3. Carbon Monoxide and Weight

a. Intercept: 1.6619 Slope:11.606

b. F*= 6.88 F(1-.05,1,23)= 4.2793

i. F*> F Do not reject. Weight is useful

c. 124.18458/539.15040= .2303338= 23.03% is explained by weight. That is low.

d. There are no outliers

e. The residuals plot has nondiscernable pattern. Therefore the line is a good fit

f. Carbon= 1.6619+ 11.606 (1)= 13.2679

4. During this project I noticed the similarities between the correlation of carbon monoxide and...