Submitted by: Submitted by Adam17
Views: 436
Words: 454
Pages: 2
Category: Science and Technology
Date Submitted: 10/09/2012 05:07 PM
1. Create a query that returns the average cost for all courses. (Round to two places).
SELECT ROUND(AVG(cost),2)
FROM course;
2. Create a query that returns the total number of Students that registered during February 2007. Alias
the column as "February_Registrations".
SELECT COUNT(registration_date) AS February_Registrations
FROM student
WHERE TO_CHAR(registration_date, 'MON YYYY') = 'FEB 2007';
3. Create a query that returns the average, highest and lowest final exam scores for Section 147.
SELECT ROUND(AVG(numeric_grade),2) AS Average, MAX(numeric_grade) As Highest, MIN(numeric_grade) As Lowest
FROM grade
WHERE grade_type_code = 'FI' and section_id = 147
4. List the city, state and number of zipcodes for all cities with more than two zipcodes. Arrange by
state and city.
SELECT city, state, COUNT(zip) AS Zipcodes
FROM zipcode
GROUP BY city, state
HAVING COUNT(zip) > 2
ORDER BY state, city;
5.Provide a list of Sections and the number of students enrolled in each section for students who
enrolled on 2/21/2007. Sort from highest to lowest on the number of students enrolled.
SELECT section_id, COUNT(enroll_date) As Enrolled
FROM enrollment
GROUP BY section_id, enroll_date
HAVING TO_CHAR(enroll_date, 'MM/DD/YYYY') = '02/21/2007'
ORDER BY Enrolled DESC, section_id DESC;
6. Create a query listing the student ID, Section ID and Average Grade for all students in Section 86.
Sort your list on the student ID and display all of the average grades with 4 decimal places.
SELECT student_id, section_id, ROUND(AVG(numeric_grade),4) As Average_Grade
FROM grade
GROUP BY student_id, section_id
HAVING section_id = 86
ORDER BY student_id;
7. Create a query to determine the number of sections that student ID 250 is enrolled in.
Your output should contain the student ID and the number of sections enrolled.
SELECT student_id, COUNT(section_id) As Sections
FROM enrollment
GROUP BY student_id
HAVING student_id = 250
8.List...