Physics

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Date Submitted: 06/30/2013 12:34 AM

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12-2 In Fig 12-38, what is the ac collector resistance? What is the ac saturation current?

12-6 What is the dc collector resistance in Fig 12-39? What is the dc saturation current?

12-10 All resistances are tripled in Fig 12-39. What is the maximum peak-to peak output?

12-14 What is the dc power supplied to the amplifier of Fig 12-38?

12-18 What is the dc power supplied to the amplifier of Fig 12-39?

12-22 The speaker of Fig 12-40 is equivalent to a load resistance of 3.2 Ohms. If the voltage across the speaker is 5 Vpp, what is the output power? What is the efficiency of the stage?

12-26 What is the quiescent collector current in Fig 12-42?

12-34 If the input voltage equals 5 Vrms in Fig 12-44, what is the peak-to-peak input voltage? If the dc voltage between the base and ground is measured, what will the voltmeter indicate?

12-44 What is the worst-case transistor power dissipation in Fig 12-44 (Q = 125)?

16-6 Two charged dust particles exert a force of 3.2 * 10^-2 N on each other. What will be the force if they are moved so that they are only one-eight as far apart?

As per Coulomb’s Law

In this case F1= 3.2 x and r1/r2=8

So final force =

16-28 What are the magnitude and direction of the electric field at a point midway between a -8.0 uC and a +7.0 uC charge 8.0 cm apart? Assume no other charges are nearby.

The distance is same for both charges = 4cm.

Electric field E

The field is directed towards the negative charge.

16-32 The electric field midway between two equal but opposite point charges is 16.0cm. What is the magnitude of the charge on each?

The electric field due to either chanrges will be in the samedirection and equal inmagnitude. So they add up.

Thus the el at the mid point is = twice the el fielddue toeither charge

Given, the separation r = 16.0 cm

Distance of the mid point is r/2.

E= 2E+ = 2E- = 2kq/(r/2)2

Hence,

q = E.r2/8k = 586x256x10-4/8x9x109

= 2084 x10-13 C =...