Submitted by: Submitted by anuja06
Views: 178
Words: 540
Pages: 3
Category: Science and Technology
Date Submitted: 08/12/2013 12:01 PM
The maximum units that can be assembled in one month are: 3000 chairs, 1000 tables and 580 bookshelves.
Total time required to assemble all the units = (3000*20)+(1000*40)+(580*15) min = 108,700 min
Total labor minutes available when all employees are available (assuming 4 weeks a month) = 150*8*5*4*60 min = 1,440,000 min
Month | No. of employees available | Total Labor minutes |
May | 130 | 1,248,000 |
June | 125 | 1,200,000 |
July | 105 | 1,008,000 |
Since the labor hours available clearly outnumber the time required in assembling maximum capacity production, leave can be granted without any issues.
ASSUMPTIONS:
* All the pending leaves for the months of May, June, July have been granted
* Ending inventory of July is zero
VARIABLES:
Variable | Description |
x1 | No. of chairs assembled in May |
x2 | No. of chairs assembled in June |
x3 | No. of chairs assembled in July |
y1 | No. of tables assembled in May |
y2 | No. of tables assembled in June |
y3 | No. of tables assembled in July |
z1 | No. of book-shelves assembled in May |
z2 | No. of book-shelves assembled in June |
z3 | No. of book-shelves assembled in July |
CONSTRAINTS:
The no. of products to be assembled, are constrained by production capacity of plant.
* x1, x2, x3 <= 3000
* y1, y2, y3 <= 1000
* z1, z2, z3 <= 580
Another constraint is in the form of availability of labor hours (it may not be a binding constraint)
* 20x1+40y1+15z1 <= 1,248,000
* 20x2+40y2+15z2 <= 1,200,000
* 20x3+40y3+15z3 <= 1,008,000
There are also some demand constraints so as to meet the sales forecast and maintain minimum inventory to minimize storage cost. Assuming that ending inventory in July is zero
* x1+30 >= 2800
* x1+30+x2 >= 2800+2300
* x1+30+x2+x3 = 2800+2300+3350
* y1+100 >= 500
* y1+100+y2 >= 500+800
* y1+100+y2+y3 = 500+800+1400
* z1+50 >= 320
* z1+50+z2 >= 320+300
*...