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Date Submitted: 09/08/2013 07:22 AM
Application of definite integrals (FAQs)
Four mark questions
1. Find the area bounded by the curve y=x2-1, x-axis and the ordinates x=0 and x=2.
Suggested answer:
[pic]
Area =[pic] where [pic]
[pic]
[pic]
[pic]
[pic]
[pic]
[pic]
2. Find the area bounded by y=sinx, x-axis between x=0 and [pic].
Suggested answer:
[pic]
By symmetry,
[pic]
[pic]
= [-0+1]
= 4 sq. units
3. Find the area of the region bounded by the line 2y=-x+8, x-axis and the ordinates x=2 and x=4.
Suggested answer:
[pic]
[pic]
In the given interval y is positive.
[pic]
[pic]
[pic]
= 5 sq. units
4. Find the area of the region between the curve y2=4x and x=3.
Suggested answer:
[pic]
y2 = 4x and x=3
A = Area OABC
= 2 Area OAB
[pic]
[pic]
[pic]
[pic]
[pic]
5. Find the area of region between the parabola y2=4ax and its latus rectum.
Suggested answer:
[pic]
y2=4ax and its L.R is x=a
A = Area OLSL|
= 2 Area OLS
[pic]
[pic]
[pic]
[pic]
[pic]
6. Find the area enclosed by the curve
y=x2-2x and x-axis.
Suggested answer:
[pic]
y=x2-2x …(i)
y+1=x2-2x+1
y+1=(x-1)2
This is a parabola of the form
(x-h)2=4a (y-k) whose vertex is [pic]
Parabola (1) meets x-axis when y=0,
[pic] 0=x2-2x [pic] x(x-2)=0
[pic] x=0,x=2
Required area is
[pic]
[pic]
7. Find the area enclosed between the parabolas y2=4ax and x2=4ay.
Suggested answer:
[pic]
Curves are [pic]
Points of intersection of the curves can be obtained by solving these equations.
[pic]
[pic] x4=64a3x
[pic] x(x3-43a3)=0...