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Date Submitted: 06/06/2013 12:31 PM

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8.1 Exercise Set

Find the first 4 terms, a^10, and a^15.

1. a^n = 4n – 1

First term – a^1 = 4 (1) - 1 = 3

Second term – a^2 = 4 (2) – 1 = 7

Third term – a^3 = 4 (3) – 1 = 11

Fourth term – a^4 = 4 (4) -1 = 15

a^10 = 4 (10) -1 = 39

a^15 = 4 (15) – 1 = 59

Plug in a^X into the given equation to solve.

8.2 Exercise Set

Find the first term and the common difference.

1.3, 8, 13, 18…

The first term (a^1) is the first term listed.

So, 3 is the first term.

The common difference (d) is found by get the first number and subtracting it by the next number to it.

d = 8 – 3 = 5

First term a^1 = 3 Common Difference (d) = 5

8.3 Exercise Set

Find the common ratio.

1.2, 4, 8, 16 …

Common Ratio = 2

To find the common ratio:

2 ( 2 / 4 = 2, 8 / 4 = 2, and so on) – divide the first number by the next to get the common ratio.

This week was very hard. lol No I’m just playing. This week was very simple, which was a surprising, because the last couple of weeks the problems and formulas were a little difficult. This week there wasn’t really a formula to try to understand, just trying to find the common number of the given problem.

Dr. Wade and classmate, I enjoy these last 5 weeks with you guys. At first the formulas was a little pain, but after going over them they wasn’t so bad. I wish everyone their best on their journey to higher learning.

Lonnie.

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