Submitted by: Submitted by carisasherman
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Words: 432
Pages: 2
Category: Business and Industry
Date Submitted: 10/01/2012 07:45 PM
Carisa Sherman
October 1, 2012
Discussion Board
Unit 1
In this week’s discussion board we were to search the internet and locate the sale price for a dream car of our own. My dream car is the 2013 Ford Explorer Four-Runner x5 listed price of $47, 500.00
1. We are going to ignore the sales tax.
2. We are to determine the annual interest rate for the loan using information from a local bank or an internet ad. Reduce this rate by 1%. This is r expressed as a decimal.
3. Interest rated by WellsFargo is 1.79% (auto loans) this rate is reduced by 1%, therefore r=0.79%
4. We are to determine the interest on your loan, using the formula:0 interest=sales price*rate*time, (I=prt)
0I=47,500.00 (0.0079)6=2251.5 or $2,251.50
5. We are to determine the total cost of the new loan, using the formula: o total cost=(sales price*rate)time +Sales Price
0 total cost =47,500.00(0.0079)6+ 47,500.00= 2251.50+47,500.00
=49,751.50 or $49,751.50
6. We are to model the total cost as a linear function. With time as the independent variable: F(t)=(pr)+p. F(t)=(47500)* 0.0079*t+(47500) F(t)=(375.25)t + 47500
7. We divide the total cost by the number of months, to determine the monthly payment. Monthly payments= Total cost/ number of months.
=49,751.50/72=690.993 or $691.00
8. Repeating steps 4 & 5 to determine the cost of the loan if the interest rate had not been reduced by 1%- how much money did you save? Interest rate without reduction is 1.79%
I=PRT
I=47,500.00 (0.0179)6=5101.5 or $5,101.50
Difference in interest =5101.50-2251.50=2850 or $2,850.00
Savings of $2,850.00
9. A summarize your finding by writing a brief statement that includes the pertinent information from the steps above; rates,totals, savings, etc……
The car loan rate for 72 months period is 1.97%. using “ simple interest car loans” this rate is reduced to 0.79%. therefore, the total cost of loan for a car with a sales price of $47,500.00 for 6 years period will be about...