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Liquid- Liquid- Extraction
Lecturer: Thomas Gamse
ao.Univ.Prof.Dipl.-Ing.Dr.techn.
Department of Chemical Engineering and Environmental Technology
Graz University of Technology
Inffeldgasse 25, A-8010 Graz
Tel.: ++43 316 873 7477
Fax: ++43 316 873 7472
email: Thomas.Gamse@TUGraz.at
Examples LiquidLiquid Extraction
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Lecturer: Dr. Gamse
Examples Liquid - Liquid Extraction
Nominating of the flows
Solvent
Feed
Mixer
Separator
Raffinate
Extract
Examples LiquidLiquid Extraction
Lecturer: Dr. Gamse
-2-
Example 1: Ternary Systems, Triangle Diagram
Two mixtures R and E, which contain both the three compounds A, B, and C, have to
mixed in the ratio 1:2. This ternary system has no miscibility gap so that all
compounds are completely soluble each other. The mixture R has a composition of
x A , R = 0,7 and x B , R = 0,2 ; the mixture E exists of x A , E = 0,1 and x B , E = 0,5 .
Please determine:
a) The points R and E in the triangle diagram and the concentration of the
active agent C and
b) the mixing point (calculation and graphical determination).
Examples LiquidLiquid Extraction
Lecturer: Dr. Gamse
-3-
a.) Mixtures in the triangle diagram
For a partial solubility of substances A and B, which is essential for extraction, all
three compounds have to be taken into account for drawing of the phase equilibrium.
For this reason triangle co-ordinates are used, where each of the vertexes represents
the pure compounds. Points at the triangle side represent the composition of the
binary system and points inside the triangle the composition of the ternary system.
The representation of a ternary point is based on the fact that the sum of the normal
distances in a equal sided triangle is corresponding to the height of the triangle. If the
height of the triangle is set 100% so result the concentrations of the single
compounds from the normal distances (see figure).
The given points R and E...