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Date Submitted: 03/14/2013 10:13 AM
FINA 3480 – Fall 2011
Group Assignment Number V– Answer Sheet
7-1. (.15)(.20) = .030
(.20)(.16) = .032
(.40)(.12) = .048
(.10)(.05) = .005
(.15)(-.05) = -.0075
.1075 or 10.75% = expected return
To calculate the standard deviation for General Foods, use the formula
n
VARi = Σ [PRi-ERi]2Pi
i=1
VARGF = [(.20-.1075)2.15] + [(.16-.1075)2.20] +
[(.12-.1075)2.40] + [(.05-.1075)2.10]
+ [(-.05-.1075)2.15]
= .00128 + .00055 + .00006 + .00033 + .00372
= .00594
Since σi = (VAR)1/2
the σ for GF = (.00594)1/2 = .0771 = 7.71%
7-2. (a) (.25)(15) + (.25)(12) + (.25)(30) + (.25)(22) = 19.75%
(b) (.10)(15) + (.30)(12) + (.30)(30) + (.30)(22) = 20.70%
(c) (.10)(15) + (.10)(12) + (.40)(30) + (.40)(22) = 23.50%
7-3. (a) (1) {3 decimal places} (1/3)2(10)2 = 11.089
+ (1/3)2( 8)2 = 7.097
+ (1/3)2(20)2 = 44.360
+ (2)(1/3)(1/3)(.6)( 8)(10) = 10.645
+ (2)(1/3)(1/3)(.2)(20)(10) = 8.871
+ (2)(1/3)(1/3)(-1)(20)( 8) = -35.485
46.577
variance = 46.577; σ = 6.82%
(2) variance = (.5)2(8)2 + (.5)2(20)2 + 2(.5)(.5)
(-1)(20)(8)
= 16 + 100 - 80
= 36
σ = 6%
(3) variance = (.5)2(8)2 + (.5)2(16)2 +
2(.5)(.5)(.3)(8)(16)
= 16 + 64 + 19.2
= 99.2
σ = 9.96%
(4) variance = (.5)2(20)2 + (.5)2(16)2 +
2(.5)(.5)(8)(20)(16)
= 100 + 64 + 128
= 292
σ = 17.09%
(b) (1) variance = (.4)2(8)2 + (.6)2(20)2 + 2(.6)(.4)
(-1)(8)(20)
= 10.24 +...