C++ Computers Paper

write a program to produce ASCII equivalent of a given number.

Soln:

#include

#include

void main()

{

clrscr();

char c;

printf("\nenter the character: ");

scanf("%c",&c);

printf("\nits ASCII equivalent is: %d",c);

getch();

}

Output:

enter the character: A

its ASCII equivalent is: 65

1. write a program to find divisor or factorial of a given number.

Soln

#include

#include

void main()

{

clrscr();

float num,i,fact=1;

printf("\nenter the number: ");

scanf("%f",&num);

i=num;

while(i>0)

{

fact=fact*i;

i--;

}

printf("\nfactorial is: %f",fact);

getch();

}

Output:

enter the number: 5

factorial is: 120.000000

2. write a program to evaluate the following algebraic expressions:

-(ax+b)/(ax-b)

-2.5log(x) + |x^2-y^2| + sqrt(2xy)

-x^5 + 10x^4 + 8x^3 + 4x +2

Soln:

#include

#include

#include

void main()

{

clrscr();

double a,x,b,y,ans1,ans2,ans3;

printf("\nenter a,b,x,y: ");

scanf("%lf%lf%lf%lf",&a,&b,&x,&y);

ans1=((a*x)+b)/((a*x)-b);

printf("\n(ax+b)/(ax-b) = %lf",ans1);

ans2=(2.5*log10(x))+( sqrt( (pow(x,2)-pow(y,2) ) * (pow(x,2)-pow(y,2)) )) +(sqrt(2*x*y));

printf("\n2.5*log(x) + |x^2-y^2| + sqrt(2*x*y) = %lf",ans2);

ans3=pow(x,5)+(10*(pow(x,4)))+(8*(pow(x,3)))+(4*x)+2;

printf("\nx^5 + 10x^4 + 8x^3 + 4x + 2 = %lf",ans3);

getch();

}

Output:

enter a,b,x,y: 2

3

4

5

(ax+b)/(ax-b) = 2.200000

2.5*log(x) + |x^2-y^2| + sqrt(2*x*y) = 16.829705

x^5 + 10x^4 + 8x^3 + 4x + 2 = 4114.000000

3. write a program to find the sum of a geometric series.

Soln.

#include

#include

#include

void main()

{

clrscr();

float r,a,temp,sum=0;

int n;

printf("\nenter the first term,...